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Question 1 of 10
1. Question
If the value of Kw is 2.9 x 10-15 at 10oC, what is the pH of pure water at 10oC?
Correct
Kw =[H3O+][OH-]
[H+] = [OH-]
therefore [H+][H+] = Kw
[H+]^2 = Kw
[H+] = SQRT(Kw)
pH = -log([H+])
pH = -log(SQRT(2.9 x 10^-15))
pH = 7.23Incorrect
Kw =[H3O+][OH-]
[H+] = [OH-]
therefore [H+][H+] = Kw
[H+]^2 = Kw
[H+] = SQRT(Kw)
pH = -log([H+])
pH = -log(SQRT(2.9 x 10^-15))
pH = 7.23 -
Question 2 of 10
2. Question
Which one of the following statements is not consistent with the kinetic-molecular theory of gases?
Correct
The kinetic molecular theory of gases describes this state of remembering as composed of tiny debris in steady movement with plenty of distance among the debris.
Incorrect
The kinetic molecular theory of gases describes this state of remembering as composed of tiny debris in steady movement with plenty of distance among the debris.
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Question 3 of 10
3. Question
A certain compound gives a negative test with ninhydrin and a positive test with Benedict’s solution. The compound is?
Correct
Protein offers blue-violet color with ninhydrin (2,2-dihydroxybenzene- 1, 3- diene) Carbohydrates provide brown-pink ppt. Ninhydrin (C9H6O4) is the hydrate form of indane-1,2,3-trione (C9H4O3). With the exception of proline and hydroxy-proline (C5H9NO3), all of the alpha-amino acids observed in proteins react with ninhydrin to provide the equal intensely colored crimson anion.
Incorrect
Protein offers blue-violet color with ninhydrin (2,2-dihydroxybenzene- 1, 3- diene) Carbohydrates provide brown-pink ppt. Ninhydrin (C9H6O4) is the hydrate form of indane-1,2,3-trione (C9H4O3). With the exception of proline and hydroxy-proline (C5H9NO3), all of the alpha-amino acids observed in proteins react with ninhydrin to provide the equal intensely colored crimson anion.
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Question 4 of 10
4. Question
Choose the correct option of the following compounds in their decreasing order of atomic radius.
Correct
Across a period, the effective nuclear charge will increase as electron shielding continue to be constant. A better powerful nuclear charge reasons extra attraction to the electrons, pulling the electron cloud toward the nucleus which leads to a smaller atomic radius.
Incorrect
Across a period, the effective nuclear charge will increase as electron shielding continue to be constant. A better powerful nuclear charge reasons extra attraction to the electrons, pulling the electron cloud toward the nucleus which leads to a smaller atomic radius.
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Question 5 of 10
5. Question
From the following options choose the correct statement for the exergonic reaction.
Correct
For exergonic reactions, the net power change is negative, and the free power of the very last products is decreased than the free power of the preliminary reactants. An exergonic response is a response that releases free power. Because this sort of response releases power in preference to consuming it, it is able to arise spontaneously, without being pressured throughout outside factors. Reactions in which chemical bonds are broken, releasing the power in the one’s bonds, are regularly exergonic reactions.
Incorrect
For exergonic reactions, the net power change is negative, and the free power of the very last products is decreased than the free power of the preliminary reactants. An exergonic response is a response that releases free power. Because this sort of response releases power in preference to consuming it, it is able to arise spontaneously, without being pressured throughout outside factors. Reactions in which chemical bonds are broken, releasing the power in the one’s bonds, are regularly exergonic reactions.
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Question 6 of 10
6. Question
What product will be formed when phenol reacts with Br2 in a CCl4 medium?
Correct
Because the non-polar solvent (i.e. CCl4) induces a weaker dipole in Br-Br as compared to the polar solvent (i.e. water), a weaker electrophile (Br+) is produced that undergoes electrophilic aromatic substitution with the benzene ring. Consequently, we get mono-bromination (introduction of one bromine atom) with Br (in CCl4) compared with tri-bromination Br (in aq.).
Incorrect
Because the non-polar solvent (i.e. CCl4) induces a weaker dipole in Br-Br as compared to the polar solvent (i.e. water), a weaker electrophile (Br+) is produced that undergoes electrophilic aromatic substitution with the benzene ring. Consequently, we get mono-bromination (introduction of one bromine atom) with Br (in CCl4) compared with tri-bromination Br (in aq.).
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Question 7 of 10
7. Question
From the following which is the most activating in electrophilic aromatic substitution?
Correct
Groups with unshared pairs of electrons, which include the amino group of aniline (C6H5NH2), are strongly activating and ortho/para-directing via way of means of resonance. Such activating groups donate the ones unshared electrons to the pi system, growing a negative charge at the ortho and para positions. These positions are as a consequence the maximum reactive in the direction of an electron-poor electrophile. The maximum electron density is placed on each ortho and para positions, even though this improved reactivity is probably offset via way of means of the steric hindrance among substituent and
Incorrect
Groups with unshared pairs of electrons, which include the amino group of aniline (C6H5NH2), are strongly activating and ortho/para-directing via way of means of resonance. Such activating groups donate the ones unshared electrons to the pi system, growing a negative charge at the ortho and para positions. These positions are as a consequence the maximum reactive in the direction of an electron-poor electrophile. The maximum electron density is placed on each ortho and para positions, even though this improved reactivity is probably offset via way of means of the steric hindrance among substituent and
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Question 8 of 10
8. Question
When a compound undergoes homolytic cleavage which chemical species is formed?
Correct
During homolytic fission of an impartial molecule with an excellent amount of electrons, free radicals are probably generated. When bonds split evenly forming free radicles where each atom getting one of the electrons.
Incorrect
During homolytic fission of an impartial molecule with an excellent amount of electrons, free radicals are probably generated. When bonds split evenly forming free radicles where each atom getting one of the electrons.
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Question 9 of 10
9. Question
What will be formed when two moles of ethyl chloride react with two moles of sodium in the presence of ether?
Correct
Wurtz response is a technique of preparation of higher alkanes from decrease alkyl halides. This is a coupling response. In this response, alkyl halides (one or more hydrogen atoms in an alkane have been replaced by halogen atoms) are reacted with sodium metal in presence of dry ether ((C2H5)2O), and higher alkanes with a good quantity of carbon atoms handiest are formed, through this method.
Incorrect
Wurtz response is a technique of preparation of higher alkanes from decrease alkyl halides. This is a coupling response. In this response, alkyl halides (one or more hydrogen atoms in an alkane have been replaced by halogen atoms) are reacted with sodium metal in presence of dry ether ((C2H5)2O), and higher alkanes with a good quantity of carbon atoms handiest are formed, through this method.
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Question 10 of 10
10. Question
From the following which has the highest melting point?
Correct
The p-dichlorobenzene molecule has a symmetrical structure. It can match properly in its crystal lattice. p-dichlorobenzene has strong intermolecular forces. Hence, it possesses the very best melting point.
Incorrect
The p-dichlorobenzene molecule has a symmetrical structure. It can match properly in its crystal lattice. p-dichlorobenzene has strong intermolecular forces. Hence, it possesses the very best melting point.